If a 4800 ohm resistor is connected to a 12 volt battery, the current flow is:
a. 2.5 mA
b.
c. 40 A
d. 400 A
Your answer "b" is not correct. "a" is the right answer.
I = E / R
= 12 / 4800
= 0.0025 Amps, which is 2.5 mA
That was the last question for this topic.